Brodhead Pietenpol Association

Original Posted By: "Jim Markle"
Dennis wrote->the width of the arc squared plus the height of the arc squared,>divided by the width of the arc.Dennis, please clarify. I tried this with a 24" wide cockpit (24" wide arc), 6" high. That's (576+36)/24 and it yields a radius of 25-1/2"... which doesn't compute. The resulting arc actually has a radius of 15". What'd I do wrong?Oscar ZunigaSan Antonio, TXmailto: taildrags(at)hotmail.comwebsite at http://www.flysquirrel.net________________________________________________________________________________

Original Posted By: "Oscar Zuniga"
I'll bet there's also a way to do it with a circle of string and twonails.....Hmmm, a changing radius....pretty close to an elipse, right?----- Original Message -----

Original Posted By: "Bert Conoly"
I did a lot of head scratching on this one. ( I raised the turtle deck 1" aboveplans.) Here's the formula I found on the web. Works a treat!http://www.josephfusco.org/Tips/tip0018.htmlMike GreenRomsey,VictoriaAUSTRALIA________________________________________________________________________________